Slide 13
Slide 13 text
© Hajime Mizuyama
Net rq. A = 90, h = 0.2 ⇒ F(n)
Lot
formation
P(3) 290 A + F(4) = 390
A + hD4
+ F(5) = 90 + 56 + 240 = 386 ⇒ F(3) (3,4) (5,7)
A + hD4
+ 2hD5
+ F(7) = 396 (8)
A + hD4
+ 2hD5
+ 4hD7
P(2) 120 A + F(3) = 476
A + hD3
+ F(4) = 90 + 58 + 300 = 448 ⇒ F(2) (2,3) (4,5)
A + hD3
+ 2hD4
(7,8)
P(1) 160 A + F(2) = 538
A + hD2
+ F(3) = 90 + 24 + 386 = 500 ⇒ F(1) (1,2) (3,4)
A + hD2
+ 2hD3
(5,7) (8)
Illustrative Example: Procedure of WW Method #2
X(3) = (1, 0, 1, 0, 0, 1)
X(2) = (1, 0, 1, 0, 0, 1, 0)
X(1) = (1, 0, 1, 0, 1, 0, 0, 1)