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cs2102: Discrete Mathematics Class 26: Counting II + Probability David Evans, Mohammad Mahmoody

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Plan Today: – Counting II – Intro to probability theory Next Tuesday: Review Next Thursday: Final Exam

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Four basic counting problems • Want to choose elements from {1, … , } Repetition IS allowed Repetition is NOT allowed Ordered (sequence) ! − ! Not ordered (set)

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Counting when order does not matter • How many ways to select a -subset of 1, … , ? • Namely: = { ∣ ⊆ , = } what is ? • Idea: define to contain -sequences using 1, … , …

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Recall Example 3 from last time How many (at most) 16-bit numbers with exactly 4 ones?

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Recall Example 4 from last time How many ways to choose 12 doughnuts from 5 varieties. Note: Order does not matter + Repetition is allowed. Seems like a new (4th) type of counting problem. We relate it to the previous problem (of no repetition) !

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Relating the Examples 3. How many (at most) 16-bit numbers with exactly 4 ones? 4. How many ways to choose 12 doughnuts from 5 varieties.

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Four basic counting problems • Want to choose elements from {1, … , } Repetition IS allowed Repetition is NOT allowed Ordered (sequence) ! − ! = ⋅ ! Not ordered (set) + − 1 − 1 = ! ! − !

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Using Counting In Proofs! • Prove = −

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“Binomial Coefficient” • + = 1≤≤ −

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Probability Theory

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Examples of Questions • A bag of 10 donuts and 5 bagels: 1. Remove one at random. What is the “probability” that it is a bagel? 2. Pick another item: What is the probability that it is a donut conditioned on 1st one being a bagel?

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Sample Space • The set of all outcomes of the experiment • Each have its own probability, adding up to 1. • Example: picking one of: 10 Donuts + 5 Bagels:

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Event • An Event ⊆ Ω: a subset of the outcomes Ω • Probability of : Pr = ∈ Pr[]

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Examples of Questions • A bag of 10 donuts and 5 bagels: 1. Remove one at random. “Probability” that it is a bagel? 2. Pick another item: What is the probability it is a donut conditioned on 1st one being a bagel?

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Conditional Probability • Events , . The probability of conditioned on happening is: Pr | = Pr ∩ Pr[]