Slide 7
Slide 7 text
created due to the nucleation of a kink-jog pair, each of length ai
, and separated by L⇥
i
(a
function of L and ai
) and is given by Eqn.(3), and the third term is the self energy of the
dislocation segments that form the kink-jog pair. In Eqns. (2) and (3), µ = 42 GPa is the
shear modulus of bulk copper and b = aCu
⇤
2
is the magnitude of the Burgers vector of all the
dislocation segments; aCu
is the 0 K lattice constant of copper. From simulations, we obtain
a1
= aCu
⇤
3
, a2
= aCu
⇤
2
, and L = 3aCu
⇤
2
. Energy expressions for all the states in our simulations
are readily obtained as a combination of Eqns. (2) and (3) with appropriate values for the
variables L, L⇥
i
, and ai
.
W(L, a, {L⇥
i
}, {ai
}) = 2 Wdis
inter
(L, ⇥, a) +
⌥
i
Wjog
inter
(L⇥
i
, ai
) +
⌥
i
2
µb2ai
4⇧(1 ⌅)
ln
ai
b
⇥
Wdis
inter
(L, ⇥, a) =
µb2
4⇧
⇧
⇧
L2 + a2 L a + L ln
⇤
2L
⇧
L2 + a2 + L
⌅⌃
Wjog
inter
(L, a) =
µb2
4⇧(1 ⌅)
⇧
2L 2
⇧
L2 + a2 2a ln
⇤
L
⇧
L2 + a2 + a
⌅⌃
WMEP
A B
(L, a, {L⇥
i
}, {ai
}, s) = WA B(L, a, {L⇥
i
}, {ai
}, s) + A⇥GSF (s)
The parameter is related to the dislocation (in this case, jogs and kinks) core radius and
can not be estimated within the linear elastic theory of dislocations. We obtain = 0.448
by fitting the energy, E = 0.27 eV, of the kink pair configuration corresponding to the
configuration in Fig. 1[schematic of the kink pair is marked in Fig. 5(b) and] from our
• α can not be determined with in linear elastic theory of dislocations
• α = 0.458 is obtained by fitting the expression for formation energy of a
thermal kink pair from simulations (ΔE = 0.27 eV)
Thermal kink pair
configuration
Dislocation model for point defect migration
b1
!1
Set 2
Set 1
a
L
a2 a1
I1
b1
!1
Set 1
Set 2
a1
a2
L
L
b1
!1
Set 1
Set 2
b
3L
(a) (b) (c)
J. P. Hirth and J. Lothe, Theory of Dislocations, (Wiley, New York, 1982)