Introductie 

Agenda • Historie • Architectuur • Start project • Views • Modules (apps) • Admin • Models • Templates 

Historie 

Begonnen in 2003 

Lawrence, KS 

Lawrence Journal 

Sinds 2005 open source 

Django Reinhardt 1910-1953 

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>= 2.5 

Google App Engine 

“My personal favorite -- and I expect that that will remain a personal favorite for a long time -- is something named Django. ... I highly recommend it.” -- Guido van Rossum 

Architectuur 

MVC Framework 

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Key philosophies 

Key philosophies • Loose coupling • Less code • Quick development • DRY • Explicit is better than implicit • Consistency 

Project 

git init GIT 

virtualenv . Virtual environment opzetten 

django-admin.py startproject [app] Start project 

python [app]/manage.py runserver dev server starten 

Profit! $$! 

python manage.py startapp articles module maken 

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INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.staticfiles', 'articles', # Uncomment the next line to enable the admin: # 'django.contrib.admin', # Uncomment the next line to enable admin documentation: # 'django.contrib.admindocs', ) app enablen settings.py 

view maken views.py from django.http import HttpResponse def hello(request): return HttpResponse("Hello world") 

from django.conf.urls.defaults import patterns, include, url # Uncomment the next two lines to enable the admin: # from django.contrib import admin # admin.autodiscover() urlpatterns = patterns('', # Examples: # url(r'^$', 'foobar.views.home', name='home'), # url(r'^foobar/', include('foobar.foo.urls')), # Uncomment the admin/doc line below to enable admin documentation: # url(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: # url(r'^admin/', include(admin.site.urls)), url(r'^$', 'articles.views.hello', name='home'), ) url toekennen urls.py 

python [app]/manage.py runserver dev server starten 

Admin 

• admin app enablen • database settings toevoegen • urls aanpassen • superuser aanmaken 

INSTALLED_APPS = ( 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'django.contrib.messages', 'django.contrib.staticfiles', 'articles', # Uncomment the next line to enable the admin: 'django.contrib.admin', # Uncomment the next line to enable admin documentation: 'django.contrib.admindocs', ) admin app enablen settings.py 

DATABASES = { 'default': { 'ENGINE': 'django.db.backends.sqlite3', 'NAME': 'example.sql', 'USER': '', 'PASSWORD': '', 'HOST': '', 'PORT': '', } } db settings settings.py 

python manage.py syncdb db settings + user 

from django.conf.urls.defaults import patterns, include, url # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Examples: # url(r'^$', 'foobar.views.home', name='home'), # url(r'^foobar/', include('foobar.foo.urls')), # Uncomment the admin/doc line below to enable admin documentation: url(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: url(r'^admin/', include(admin.site.urls)), url(r'^$', 'articles.views.hello', name='home'), ) url enablen urls.py 

python [app]/manage.py runserver dev server starten 

http://127.0.0.1:8000/admin admin openen 

Models! 

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from django.db import models from datetime import * class Article(models.Model): created_at = models.DateTimeField(auto_now_add=True, default=datetime.now()) updated_at = models.DateTimeField(auto_now=True) publish_at = models.DateTimeField(default=datetime.now()) title = models.CharField(max_length=255) intro = models.TextField(null=False) body = models.TextField(null=False) article model models.py 

python [app]/manage.py syncdb db syncen 

from django.contrib import admin from app.articles.models import * admin.site.register(Article) toevoegen aan admin articles/admin.py 

python [app]/manage.py runserver dev server starten 

http://127.0.0.1:8000/admin admin openen 

article aanmaken 

Templates 

view wijzigen views.py from django.http import HttpResponse from django.shortcuts import render_to_response from articles.models import * def hello(request): return HttpResponse("Hello world") def article(request,id): article = Article.objects.get(pk=id) return render_to_response( 'view.html', locals(), context_instance=RequestContext(request) ) 

from django.conf.urls.defaults import patterns, include, url # Uncomment the next two lines to enable the admin: from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', # Examples: # url(r'^$', 'foobar.views.home', name='home'), # url(r'^foobar/', include('foobar.foo.urls')), # Uncomment the admin/doc line below to enable admin documentation: url(r'^admin/doc/', include('django.contrib.admindocs.urls')), # Uncomment the next line to enable the admin: url(r'^admin/', include(admin.site.urls)), url(r'^$', 'articles.views.hello', name='home'), url(r'^article/(?P[0-9]+)$', 'articles.views.article', name='articleView'), ) url enablen urls.py 

import os PROJECT_PATH = os.path.realpath(os.path.dirname(__file__)) TEMPLATE_DIRS = ( PROJECT_PATH + '/templates/', ) template path setten settings.py 

{{article.title}}

{{article.intro}}

{{article.body}}

template maken templates/view.html 

http://127.0.0.1:8000/article/1 url openen 

done!