Slide 12
Slide 12 text
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Performing the line integral on triangular in case of linear
function m=Md+v (M:matrix and V: vector) can be
simplified by stating mean and covariance,
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Consider model parameter m
1
which is mean of data,
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That is, M = [ 1, 1, 1, . . . , 1]/N and v = 0. Suppose that
the data are uncorrelated and all have the same mean (d)
and variance σ
d
2..
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Hence model parameter m
1
has distribution P (m
1
) denan
mean m
1
=d dan variance σ
d
2=σ
d
2 /N.
So, m
1
close to the true mean is proportional to N-1/2
2.3 Function of Random Variables
〈d 〉=M 〈d 〉+v [cov m]=M [cov d ] MT
〈m
1
〉=M 〈d 〉 (m
1
)=M [cov d ] MT =σ
d
2 /N
m
1
=1/N ∑
i
N
d
i
=(1/N )[1,1,1,...,1]d