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Let’s write a parser! DENIS DEFREYNE / RUG˸˸B / MAY 12TH, 2016

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1. Language 2

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I am Denis. 3

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But how do you know that I am Denis? 4

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But how do you know that I am Denis? I told you. I wrote it down. Tobi introduced me. You might have seen me before. Etc. 5

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But how do you know that I am Denis? You understand English. 6

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Computers are stupid. 7

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8 $ git commit --message="Fix bugs"

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9 def greet(name) puts "Hello, #{name}" end

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Text forms a language, but computers don’t know that. 10

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2. Parsing 11

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Basic idea: 12 Parser objects that are small, composable, and purely functional.

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13 def read(input, pos)

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14 def read(input, pos) Success.new(pos + 1) end

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15 def read(input, pos) Failure.new(pos) end

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16 char("H") Succeeds if the next character is the given one.

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17 char("H").apply("Hello")

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17 H e l l o char("H").apply("Hello")

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17 H e l l o 0 1 2 3 4 char("H").apply("Hello")

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17 H e l l o 0 1 2 3 4 char("H").apply("Hello")

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17 H e l l o 0 1 2 3 4 char("H").apply("Hello")

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17 H e l l o 0 1 2 3 4 char("H").apply("Hello") Success(position = 1)

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18 char("H").apply("Adiós")

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18 A d i ó s 0 1 2 3 4 char("H").apply("Adiós")

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18 A d i ó s 0 1 2 3 4 char("H").apply("Adiós")

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18 A d i ó s 0 1 2 3 4 char("H").apply("Adiós")

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Failure(position = 0) 18 A d i ó s 0 1 2 3 4 char("H").apply("Adiós")

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19 if input[pos] == @char Success.new(pos + 1) else Failure.new(pos) end

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20 seq(a, b) Succeeds if both given parsers succeed in sequence.

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21 seq(char("H"), char("e")).apply("Hello")

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H e l l o 21 0 1 2 3 4 seq(char("H"), char("e")).apply("Hello")

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H e l l o 21 0 1 2 3 4 seq(char("H"), char("e")).apply("Hello")

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H e l l o 21 0 1 2 3 4 seq(char("H"), char("e")).apply("Hello")

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H e l l o 21 0 1 2 3 4 seq(char("H"), char("e")).apply("Hello")

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H e l l o 21 0 1 2 3 4 seq(char("H"), char("e")).apply("Hello") Success(position = 2)

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22 seq( char("H"), char("e"), char("l"), char("l"), char("o"), )

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23 string(s) Succeeds if all characters in the given string can be read in sequence.

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H e l l o 24 0 1 2 3 4 string("Hello").apply("Hello")

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H e l l o 24 0 1 2 3 4 string("Hello").apply("Hello")

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H e l l o 24 0 1 2 3 4 string("Hello").apply("Hello")

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H e l l o 24 0 1 2 3 4 string("Hello").apply("Hello") Success(position = 5)

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25 eof() Succeeds at the end of input; fails otherwise.

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H e l l o 26 0 1 2 3 4 seq(string("Hello"), eof).apply("Hello")

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H e l l o 26 0 1 2 3 4 seq(string("Hello"), eof).apply("Hello")

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H e l l o 26 0 1 2 3 4 seq(string("Hello"), eof).apply("Hello")

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H e l l o 26 0 1 2 3 4 seq(string("Hello"), eof).apply("Hello")

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H e l l o 26 0 1 2 3 4 seq(string("Hello"), eof).apply("Hello") Success(position = 5)

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27 0 1 2 3 4 5 H e l l o ! seq(string("Hello"), eof).apply("Hello!")

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27 0 1 2 3 4 5 H e l l o ! seq(string("Hello"), eof).apply("Hello!")

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27 0 1 2 3 4 5 H e l l o ! seq(string("Hello"), eof).apply("Hello!")

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27 0 1 2 3 4 5 H e l l o ! seq(string("Hello"), eof).apply("Hello!")

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27 0 1 2 3 4 5 Failure(position = 5) H e l l o ! seq(string("Hello"), eof).apply("Hello!")

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28 alt(a, b) Succeeds if either of the given parsers succeed.

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A d i ó s 29 0 1 2 3 4 alt(char("H"), char("A")).apply("Adiós")

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A d i ó s 29 0 1 2 3 4 alt(char("H"), char("A")).apply("Adiós")

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A d i ó s 29 0 1 2 3 4 alt(char("H"), char("A")).apply("Adiós")

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A d i ó s 29 0 1 2 3 4 alt(char("H"), char("A")).apply("Adiós") Success(position = 1)

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30 whitespace_char = alt(char(" "), char("\t"))

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31 optional(p) Succeeds always, but only advances if p succeeds.

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32 repeat(p) Succeeds always, and attempts to apply p as often as possible.

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33 repeat(whitespace_char)

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34 intersperse(a, b) Alternates between a and b., always ending with a.

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35 intersperse(char("a"), char(",")).apply("a,a,b")

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a , a , b 35 0 1 2 3 4 intersperse(char("a"), char(",")).apply("a,a,b")

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a , a , b 35 0 1 2 3 4 intersperse(char("a"), char(",")).apply("a,a,b")

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a , a , b 35 0 1 2 3 4 intersperse(char("a"), char(",")).apply("a,a,b")

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a , a , b 35 0 1 2 3 4 intersperse(char("a"), char(",")).apply("a,a,b")

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a , a , b 35 0 1 2 3 4 intersperse(char("a"), char(",")).apply("a,a,b") Success(position = 3)

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36 etc.

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37 720 6 29530

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38 
 digit = alt( *('0'..'9') .map { |c| char(c) } )

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39 
 digit = char_in('0'..'9')
 
 


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40 nat_number = seq(digit, repeat(digit))

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41 nat_number = repeat1(digit)

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42 nat_number = repeat1(digit) .capture

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42 nat_number = repeat1(digit) .capture Success(position = 3, data = "123")

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43 nat_number = repeat1(digit) .capture .map(&:to_i)

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43 nat_number = repeat1(digit) .capture .map(&:to_i) Success(position = 3, data = 123)

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44 def read(input, pos)

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45 def read(input, pos) Success.new(pos + 1) end

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46 def read(input, pos) Success.new(pos + 1, "blahblah") end

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47 first,last,age Denis,Defreyne,29

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48

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48 field =
 repeat(char_not(',', "\n")).capture


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48 field =
 repeat(char_not(',', "\n")).capture
 line =
 field.intersperse(char(','))


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48 field =
 repeat(char_not(',', "\n")).capture
 line =
 field.intersperse(char(','))
 file =
 seq(
 line.intersperse(char("\n")),
 end_of_input,
 )

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49 [ ["first_name", "last_name", "age"], ["Denis", "Defreyne", "29"], ]

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50 add(1, mul(2, 3)) mul(2, 3)

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51 lparen = char('(') rparen = char(')') comma = char(',')

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52 expr = alt(lazy { funcall }, nat_number)

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53 funcall = seq( identifier, lparen, arglist, rparen, )

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54 letter =
 char_in('a'..'z')
 identifier =
 repeat1(letter).capture

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55

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55 arglist =
 seq(expr, arglist_tail)


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55 arglist =
 seq(expr, arglist_tail)
 arglist_tail =
 repeat(seq(comma, whitespace, expr))

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56

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56 expr_list =
 expr.intersperse(char("\n"))


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56 expr_list =
 expr.intersperse(char("\n"))
 program =
 seq(expr_list, eof)

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57 [ ["add", 1, ["mul", 2, 3]], ["mul", 2, 3], ]

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And that is how you can write a parser. 58

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github.com/ddfreyne/d-parse 59

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github.com/ddfreyne/d-parse 59

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github.com/ddfreyne/d-parse 59

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60 My name is Denis Defreyne. Ready to parse your questions. Find me at [email protected], or @ddfreyne on Twitter.