Slide 7
Slide 7 text
1. Choose a decryption number(D) where
the decryption times the encryption
number to the modulus of (phi)N is equal
to 1
2. D and N are the private key
5*D(mod 6) = 1
D = every 6th multiple, so we
choose 11
D=11
Decryption
Remember: P = 2 , Q = 7, N = 14, (phi)N= 6, E=5
M= Message, C = Cypher Text
Decrypt using the equation
CD mod N = M