Slide 34
Slide 34 text
x
?=0
H;,j
!
ok, by continuity.
'j /
2 Im( I)
!
exclude this case.
Exclude hyperplanes:
HI,j
d
s
j
(¯
y,
¯) = |h
'j,
¯
y I ˆ
x¯(¯
y
)i| 6
Case 2: ds
j
(y, ) = and 'j
2 Im( I)
Case 1: ds
j
(y, ) <
H =
[
{Hs,j
\ 'j /
2 Im( I)}
Hs,j = (y, ) \ ds
j
(¯
y, ¯) =
then
ds
j(¯
y, ¯) = ¯ !
ok.
Proof
ˆ
x¯
(¯
y)
I
= +
I
¯
y ¯(
I I
) 1sI
To show:
8 j /
2 I,
Case 3: ds
j
(y, ) = and
I = supp(s)