Linked Lists Week 3 What’s a good memory you have from this week? -> I had an amazingly tasty burger 🍔 

Addressing Feedback - Panel was well-received - Office hours are posted on course portal now - Zoom issues should be resolved 

Linked Lists 

What is a Linked List? Individual elements (nodes) that each hold two pieces of information: 1) data (integer, string, anything!) 2) reference to the next node 

No content

Why are they useful? 

Why are they useful? Web browser’s history (previous / next page) 

Why are they useful? Web browser’s history (previous / next page) Memory management (blocks of memories) 

Why are they useful? Web browser’s history (previous / next page) Memory management (blocks of memories) Hash tables (resolving collisions) 

Types of Linked Lists 

Singly linked Doubly linked Circularly linked Types of Linked Lists 

Singly linked Doubly linked Circularly linked Types of Linked Lists 

Pros and Cons Always think about space / time complexity when choosing a data structure! 

Pros and Cons Always think about space / time complexity when choosing a data structure! Good for:
 - insertion / deletion from one end 
 
 

Pros and Cons Always think about space / time complexity when choosing a data structure! Good for:
 - insertion / deletion from one end 
 
 Bad for:
 - searching 

Pros and Cons Always think about space / time complexity when choosing a data structure! Good for:
 - insertion / deletion from one end 
 
 Bad for:
 - searching https://guides.codepath.org/compsci/Linked-Lists 

Linked List Tips and Tricks 

Linked List Tips and Tricks Take multiple passes through the linked list
 - get length 
 - save other information about contents 

Linked List Tips and Tricks Take multiple passes through the linked list
 - get length 
 - save other information about contents Two pointers
 - ‘race car’ strategy with one regular pointer, and one fast pointer 

Linked List Tips and Tricks Take multiple passes through the linked list
 - get length 
 - save other information about contents Two pointers
 - ‘race car’ strategy with one regular pointer, and one fast pointer Dummy node
 - helpful for preventing errors when returning ‘head’ (merging lists, deleting from lists) 

Understand Match Pseudocode / Plan Implement Review Evaluate 

Plan / Pseudocode Start to figure out how you would solve the problem Can you create any ‘magic’ helper methods that would simplify the solution? (ie : getLength(), reverse() ) Talk through different approaches you can take, and their tradeoffs Be able to verbally describe your approach and explain how an example input would produce the desired output 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 1->2->3->4->5, n = 2
 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 1->2->3->4->5, n = 2
 return 1->2->3->5 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 1, n = 1
 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 1, n = 1
 return null 

Example: Remove Nth Node from End of List Understand: Always start by understanding the question and running through an example 1->2->3->4->5, n = 2
 return 1->2->3->5 Let’s assume we start without any time / space constraints. So our goal is to figure out ANY kind of solution to produce the right answer Any other questions?? 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 -> We can also take a pass to get the length of the linked list 
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 -> We can also take a pass to get the length of the linked list Plan : What are some different ways we can solve this problem?
 
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 -> We can also take a pass to get the length of the linked list Plan : What are some different ways we can solve this problem?
 1) We can store the elements in an array, get the length of the array, and then rebuild our list excluding the nth to last node
 
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 -> We can also take a pass to get the length of the linked list Plan : What are some different ways we can solve this problem?
 1) We can store the elements in an array, get the length of the array, and then rebuild our list excluding the nth to last node
 2) We can follow the first idea, but instead of storing things in an array, remove the reference to the nth to last node the second time we iterate through the list
 

Example: Remove Nth Node from End of List Match : Are there any special techniques that we can use to help make this easier?
 -> We can take a first pass through the linked list to store the elements in an array 
 -> We can also take a pass to get the length of the linked list Plan : What are some different ways we can solve this problem?
 1) We can store the elements in an array, get the length of the array, and then rebuild our list excluding the nth to last node
 2) We can follow the first idea, but instead of storing things in an array, remove the reference to the nth to last node the second time we iterate through the list
 What would be the space / time complexity of our solution? 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3.
 
 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3. Since n = 1, that means we want to remove the 3 -1 = 2 node (with index starting at 0)
 
 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3. Since n = 1, that means we want to remove the 3 -1 = 2 node (with index starting at 0)
 
 As we iterate through the list..
 at node 1 -> numberOfNodesSeen = 0 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3. Since n = 1, that means we want to remove the 3 -1 = 2 node (with index starting at 0)
 
 As we iterate through the list..
 at node 1 -> numberOfNodesSeen = 0
 at node 2-> numberOfNodesSeen = 1 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3. Since n = 1, that means we want to remove the 3 -1 = 2 node (with index starting at 0)
 
 As we iterate through the list..
 at node 1 -> numberOfNodesSeen = 0
 at node 2-> numberOfNodesSeen = 1
 at node 3 -> numberOfNodesSeen = 2 -> at this point we need to set node 2’s next to be node 3’s next! 

Example: Remove Nth Node from End of List Our approach:
 1) make initial pass through linked list to get length
 2) make second pass to remove any reference to nth to last node
 
 Let’s draw out how this might work with an example
 Given linked list 1->2->3, n = 1 (we want to return 1->2) First pass, we get length = 3. Since n = 1, that means we want to remove the 3 -1 = 2 node (with index starting at 0)
 
 As we iterate through the list..
 at node 1 -> numberOfNodesSeen = 0, previousNode = null
 at node 2-> numberOfNodesSeen = 1, previousNode = 1
 at node 3 -> numberOfNodesSeen = 2, previousNode = 2 -> we set previousNode.next = node.next (node 3’s next = null) 

Breakout Rooms - Turn on your camera - Assign a timekeeper
 - Breakout rooms will close at 11:30 am PT
 - Take a 5 min break right before then! - Open the Course Portal and go to this week’s Session #2 tab
 - Read the At a Glance
 - Start with the Icebreaker! - If your pod needs help, post a message in the @se102-help-fall21 slack channel and tag @se102-tas 

Evaluating companies 

Evaluating companies Glassdoor reviews Researching current people who work at the company on LinkedIn 

Questions for me? 

Questions for me? Work Life Balance 

Questions for me? Work Life Balance - How does the team figure out what to work on in the next 3-6 months? - How does the team tackle tech debt? - What is a typical release process? - Weekly? Biweekly? - How does the team prepare for releases? - How is the release monitored afterwards? - Are there oncall schedules? 

Questions for me? Career Growth 

Questions for me? Career Growth - What do you see me working on in my first 3-6 months on the job? - How do people on the team get feedback usually? 

Questions for me? General - What are some challenging projects you’ve worked on in the past 3-6 months? - What kind of meetings do you usually have in a week? 

Questions for me? Other questions? 

Survey