Upgrade to Pro — share decks privately, control downloads, hide ads and more …

Práctica 3: Math 2

Avatar for adominguezc83 adominguezc83
May 06, 2012
0
1k

Práctica 3: Math 2

Avatar for adominguezc83

adominguezc83

May 06, 2012
Tweet

More Decks by adominguezc83

See All by adominguezc83
Práctica Final
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 3: Math 3
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 3: Math 1
Avatar for adominguezc83 adominguezc83
0
990
Práctica 3: -2 tablas y tabuladores pt.3
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 3: -2 tablas y tabuladores pt.2
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 3: -2 tablas y tabuladores
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 1: Viñietas, esquema
Avatar for adominguezc83 adominguezc83
0
1.1k
Práctica Real Madrid
Avatar for adominguezc83 adominguezc83
0
1k
Práctica 3: columnas
Avatar for adominguezc83 adominguezc83
0
1k

Featured

See All Featured
XXLCSS - How to scale CSS and keep your sanity
Avatar for Zaharenia Atzitzikaki sugarenia
249
1.3M
Producing Creativity
Avatar for Steve Smith orderedlist
PRO
348
40k
How GitHub (no longer) Works
Avatar for Zach Holman holman
316
150k
Prompt Engineering for Job Search
Avatar for Mfonobong Umondia mfonobong
0
230
Six Lessons from altMBA
Avatar for Skipper Chong Warson skipperchong
29
4.2k
Reflections from 52 weeks, 52 projects
Avatar for Jefferson Lam jeffersonlam
356
21k
The Myth of the Modular Monolith - Day 2 Keynote - Rails World 2024
Avatar for Eileen M. Uchitelle eileencodes
26
3.4k
Statistics for Hackers
Avatar for Jake VanderPlas jakevdp
799
230k
Making the Leap to Tech Lead
Avatar for Ryan Cromwell cromwellryan
135
9.8k
The Impact of AI in SEO - AI Overviews June 2024 Edition
Avatar for Aleyda Solis aleyda
5
780
Getting science done with accelerated Python computing platforms
Avatar for Jacob Tomlinson jacobtomlinson
2
150
Mind Mapping
Avatar for Hélio Medeiros helmedeiros
PRO
1
130

Transcript

  1. Ejercicio 2: f (x)=a n xn+a n−1 +xn−1+⋯+a 1 x+a

    0 f (x)=∑ r=0 n a r xr e=lim n →∞ (1+ 1 n ) n