if there exists a surjective function from ℕ to . A set is infinite, if there is no bijection between and any ℕ% . A set is countably infinite if it is countable and it is infinite. A set is countably infinite if there exists a bijection between and ℕ. Is the set of Tsils countable?
Proof by induction: ∷= ∀ sets where = . > . Base case: 0 : = ∅. = {∅}. = 1 > = 0. Inductive case: ∀ ∈ ℕ. ⇒ + 1 . for all sets where = + 1, ∃ where = , ∉ . = ∪ ⇒ > ⇒ + 1 > + 1 Since () includes all elements of () and include , this means > ⇒ ( + 1). Therefore, always holds, so we can conclude for all sets , > | |.
Proof by induction: ∷= ∀ sets where = . > . Base case: 0 : = ∅. = {∅}. = 1 > = 0. Inductive case: ∀ ∈ ℕ. ⇒ + 1 . for all sets where = + 1, ∃ where = , ∉ . = ∪ ⇒ > ⇒ + 1 > + 1 Since () includes all elements of () and include , this means > ⇒ ( + 1). Therefore, always holds, so we can conclude for all sets , > | |. 1 2 3 4 5 6 7 8 9 10 11 Which step is wrong?
actually Cantor’s proof, although it is commonly called Cantor’s Theorem. Cantor came up with the diagonalization argument we will see next; this proof is believed to have been first done by Hessenberg (1906).