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Using boolean logic to deal with dates
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Irina Bednova
October 30, 2014
Programming
0
480
Using boolean logic to deal with dates
The unexpected application of Karnaugh maps in a Rails project
Irina Bednova
October 30, 2014
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Transcript
For fun Using Boolean logic to deal with dates
The problem
The problem Parse a string to a Date object
The problem • Date could be in the mm/dd/yyyy format
The problem • Date could be in the mm/dd/yyyy format
• Date could be in any format recognisable by Date.parse
The problem • Date could be in the mm/dd/yyyy format
• Date could be in any format recognisable by Date.parse • Except the dd/mm/yyyy format
month_day_year = Date.strptime(string, "%m/%d/%Y") rescue nil
month_day_year = Date.strptime(string, "%m/%d/%Y") rescue nil generic_parse = Date.parse(string) rescue
nil
month_day_year = Date.strptime(string, "%m/%d/%Y") rescue nil generic_parse = Date.parse(string) rescue
nil day_month_year = Date.strptime(string, "%d/%m/%Y") rescue nil
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 0 1 0 0 1 1 1 0 0 1 0 1 1 1 0 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 0 1 1 1 0 0 1 0 1 X 1 1 0 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 1 0 1 1 1 0 0 1 0 1 X 1 1 0 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 1 0 1 1 0 1 0 0 1 0 1 X 1 1 0 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 X 1 1 0 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 X 1 1 0 X 1 1 1
month_day_year generic_parse day_month_year result 0 0 0 0 0 0
1 X 0 1 0 1 0 1 1 0 1 0 0 1 1 0 1 X 1 1 0 X 1 1 1 1
Makes your boolean functions simpler! Karnaugh map
0 X 0 1 1 X 1 X generic_parse *
day_month_year month_day_year 1 0 00 01 11 10
0 X 0 1 1 X 1 X generic_parse *
day_month_year month_day_year 1 0 00 01 11 10
0 X 0 1 1 X 1 X generic_parse *
day_month_year month_day_year 1 0 00 01 11 10
0 X 0 1 1 X 1 X generic_parse *
day_month_year month_day_year 1 0 00 01 11 10
month_day_year 0 X 0 1 1 X 1 X generic_parse
* day_month_year month_day_year 0 00 01 11 10 1
month_day_year ∨ ¬generic_parse ∧ day_month_year 0 X 0 1 1
X 1 X generic_parse * day_month_year month_day_year 0 00 01 11 10 1
month_day_year ∨ ¬generic_parse ∧ day_month_year ∨ generic_parse ∧ ¬day_month_year 0
X 0 1 1 X 1 X generic_parse * day_month_year month_day_year 0 00 01 11 10 1
((month_day_year ? 1 : 0) + ((day_month_year ? 1 :
0) ^ (generic_parse ? 1 : 0)) == 0) month_day_year || generic_parse
Thank you! Irina Bednova @jafrog www.jafrog.com