List[(Int, String)] = List((1,a), (2,b), (3,c)) • List(1, 3, 5, 7, 9).partition((i: Int) => i > 5) res1: (List[Int], List[Int]) = (List(7, 9),List(1, 3, 5)) • List(1,2,3,4,5).find((i: Int) => i > 3) res1: Option[Int] = Some(4) • and can be chained... numbers.filter(...).map(...) Thursday, 19 July 12