men. Department Men Women Applicants Admitted Applicants Admitted A 825 62% 108 82% B 560 63% 25 68% C 325 37% 593 34% D 417 33% 375 35% E 191 28% 393 24% F 272 6% 341 7% Total 8442 44% 4321 35%
108 82% B 560 63% 25 68% C 325 37% 593 34% D 417 33% 375 35% E 191 28% 393 24% F 272 6% 341 7% Total 8442 44% 4321 35% Women tended to apply to competitive departments with low rates of admission
– politicians, judges, and so on – are making decisions based on statistical studies, and yet they don’t understand even basic things like Simpson’s paradox. - Michael Nielsen “ ”
Z p(y|w, do(x), do(z)) = p(y|w, do(x), z) ⇒ When can we ignore the act of intervention? If removing the influence of Z makes Y and Z unrelated, it makes no difference whether we have intervention on Z or not. Z HAS NO POWER HERE
Z - pa(W) p(y|w, do(x), do(z)) = p(y|w, do(x)) ⇒ When can we ignore an intervention variable entirely? If Z only affects known variables (X and W), Y has nothing to do with Z.
t)⋅p(t|s) = Σ t p(c|do(s), do(t))⋅p(t|s) = Σ t p(c|do(t))⋅p(t|s) = Σ t (Σ s p(c|do(t), s)⋅p(s|do(t)))⋅p(t|s) = Σ t (Σ s p(c|t, s)⋅p(s|do(t)))⋅p(t|s) S C H T (C ⊥ T|S) GS, T RULE 2
p(c|do(s)) = Σ t p(c|do(s), t)⋅p(t|do(s)) = Σ t p(c|do(s), t)⋅p(t|s) = Σ t p(c|do(s), do(t))⋅p(t|s) = Σ t p(c|do(t))⋅p(t|s) = Σ t (Σ s p(c|do(t), s)⋅p(s|do(t)))⋅p(t|s) = Σ t (Σ s p(c|t, s)⋅p(s|do(t)))⋅p(t|s) = Σ t (Σ s p(c|t, s)⋅p(s))⋅p(t|s)
90% cancer Non-smoker 2.5% 5% cancer 47.5% 10% cancer p(c|do(s)) = 45.25% p(c|do(~s)) = 47.5% ➭ ➭Smoking reduces chance of getting cancer! * * This is not true because the numbers we’re using are not real