C(1 + |s|p) 8s 2 R sf ( s ) > 0 for s large ", C > 0 ps := ( 1 N = 1, 2 (N + 2)/(N 2) N 3 f 2 C1(R) T. Cazenave, F. Dickstein, F. B. Weissler (2010) 1 < p < ps sf0(s) (1 + ")f(s) 8s 2 R 14
B := {u0 2 X | Tu0 < 1} ࣌ؒେҬղ രൃղ X = C0(⌦) ղۭؒ ತͰͳ͍ɻ G 1 < p < ps f(s) = |s|p 1s 8 > < > : ut u = f(u) in ⌦ ⇥ (0, T) u = 0 on @⌦ ⇥ (0, T) u(x, 0) = u0(x) in ⌦ 22