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KuoE0
February 20, 2013
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[ACM-ICPC] Top-down & Bottom-up
KuoE0
February 20, 2013
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Transcript
Top-down & Bottom-up ֲࢸݢʢKuoE0ʣ
[email protected]
KuoE0.ch
Attribution-ShareAlike 3.0 Unported (CC BY-SA 3.0) http://creativecommons.org/licenses/by-sa/3.0/ Latest update: Feb
27, 2013
Top-down ሡେԽҝখɼ࠶ճᕧٻղɻ
Top-down ሡେԽҝখɼ࠶ճᕧٻղɻ
Top-down ሡେԽҝখɼ࠶ճᕧٻղɻ
Bottom-up ༝ቮղܾখɼஞ㑊ਪҠࢸେɻ
Bottom-up ༝ቮղܾখɼஞ㑊ਪҠࢸେɻ
Recursion қ༗ଠۃɼੋੜၷّɻၷّੜ࢛ɼ࢛ੜീ܋ɻʬқၚʭ ར༻ಉᒬతํ๏ෆᏗతࡉ҃ṧۙҊɻ
Fibonacci Sequence fib(5)
Fibonacci Sequence fib(5) fib(4) fib(3)
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(3)
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(2) fib(1) fib(3)
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(2) fib(1) fib(0) fib(1)
fib(3)
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(2) fib(1) fib(0) fib(1)
fib(3) 1 0 1
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(2) fib(1) fib(0) fib(1)
fib(3) 1 0 1 1 2
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(3) 1 0 1 1 2
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(3) 1 0 1 1 2 1 0 1 3
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(2) fib(3) fib(1) 1 0 1 1 2 1 0 1 3
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(1) fib(2) fib(3) fib(0) fib(1) 1 0 1 1 2 1 0 1 3
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(1) fib(2) fib(3) fib(0) fib(1) 1 0 1 1 2 1 0 1 3 1 0 1
Fibonacci Sequence fib(5) fib(4) fib(3) fib(2) fib(1) fib(2) fib(1) fib(0)
fib(0) fib(1) fib(1) fib(2) fib(3) fib(0) fib(1) 1 0 1 1 2 1 0 1 3 1 0 1 1 2 5
int fib( int x ) { if ( x <=
0 ) return 0; if ( x == 1 ) return 1; return fib( x - 1 ) + fib( x - 2 ); } int main() { int ret = fib( 10 ); return 0; }
Iteration ಓੜҰɼҰੜೋɼೋੜࡾɼࡾੜᤈɻʬࢠʭ ෆᏗతར༻ቮɼ࣋᠃తٻग़݁ՌҎṧۙҊɻ
Fibonacci Sequence 0 1
Fibonacci Sequence 0 1 1
Fibonacci Sequence 0 1 1 2
Fibonacci Sequence 0 1 1 2 3
Fibonacci Sequence 0 1 1 2 3 5
int main() { int f0 = 0, f1 = 1,
f2; for ( int i = 0; i < 10; ++i ) { f2 = f0 + f1; f0 = f1, f1 = f2; } return 0; }
ᬇጯఱ্༗ɼຌਓጯᙛ༻ᅲɻ
POJ 1664 - ์ᣄՌ Practice Now
reference •http://www.csie.ntnu.edu.tw/~u91029/ IterativeRecursive.html
Thank You for Your Listening.