from customer where name <> ‘Brian’; select * from customer where name like ‘B%’; select * from customer where id in (1,2,3); select * from customer where id = 2 and age >= ‘30’; select * from customer where id = 2 or age >= ‘30’; 14 絞り込み( WHERE) 「!=」とも書ける id name age city 1 Alice 40 Chicago 2 Brian 23 Seattle 3 Cindy 29 Chicago 4 David 36 Boston