the equation a3 + b3 = c3 + d3, (1 ≤ a, b, c, d ≤ 1000) n = 1000 for a from 1 to n for b from 1 to n for c from 1 to n for d from 1 to n if a3 + b3 == c3 + d3 print a, b, c, d O(N4) n = 1000 for a from 1 to n for b from 1 to n for c from 1 to n for d from 1 to n if a3 + b3 == c3 + d3 print a, b, c, d break O(N4) n = 1000 for a from 1 to n for b from 1 to n for c from 1 to n d = pow(a3 + b3 - c3, 1/3) if a3 + b3 == c3 + d3 print a, b, c, d O(N3) 42 a3 + b3 - c3 = d3