head head -n -n 2 2 employees.csv employees.csv 11523 11523, ,"1953-01-25" "1953-01-25", ,"Yuguang" "Yuguang", ,"Pezzoli" "Pezzoli", ,"F" "F", ,"1992-12-23" "1992-12-23" 11524 11524, ,"1955-10-26" "1955-10-26", ,"Xiadong" "Xiadong", ,"Standera" "Standera", ,"M" "M", ,"1988-09-20" "1988-09-20" SQL SQL > > select select * * from from employees employees limit limit 2 2; ; + +--------+------------+------------+-----------+--------+------------+ --------+------------+------------+-----------+--------+------------+ | | emp_no emp_no | | birth_date birth_date | | first_name first_name | | last_name last_name | | gender gender | | hire_date hire_date | | + +--------+------------+------------+-----------+--------+------------+ --------+------------+------------+-----------+--------+------------+ | | 10001 10001 | | 1953 1953- -09 09- -02 02 | | Georgi Georgi | | Facello Facello | | M M | | 1986 1986- -06 06- -26 26 | | | | 10002 10002 | | 1964 1964- -06 06- -02 02 | | Bezalel Bezalel | | Simmel Simmel | | F F | | 1985 1985- -11 11- -21 21 | | + +--------+------------+------------+-----------+--------+------------+ --------+------------+------------+-----------+--------+------------+ Remember we used an unsorted tablespace le. Copyright @ 2025 Oracle and/or its affiliates. $ grep Facello employees $ grep Facello employees. .csv csv | | grep Georgi grep Georgi 55649 55649, ,"1956-01-23" "1956-01-23", ,"Georgi" "Georgi", ,"Facello" "Facello", ,"M" "M", ,"1988-05-04" "1988-05-04" 10001 10001, ,"1953-09-02" "1953-09-02", ,"Georgi" "Georgi", ,"Facello" "Facello", ,"M" "M", ,"1986-06-26" "1986-06-26" 45