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I am bad at my job.
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Matt Robenolt
September 28, 2017
Technology
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I am bad at my job.
App Academy - September 28th 2017
Matt Robenolt
September 28, 2017
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Transcript
I am bad at my job. App Academy September 28th
2017 Matt Robenolt Matt
hello @mattrobenolt
Principal Software Engineer
This computer stuff is really hard.
None
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; }
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } $ ./program
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } $ ./program 10 20 619512036
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } $ ./program 10 20 619512036 $ ./program 10 20 369033241
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 0x0004 4 bytes 0x0008 0x000C 0xFFFF
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 0x0004 4 bytes 0x0008 0x000C 0xFFFF 0x0000 (0)
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 0x0004 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0000 (0)
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0000 (0) 0x0004
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0000 (0) 0x0004 “address of things” + (i * sizeof(int))
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0000 (0) 0x0004 0x0004 + (0 * 4) == 0x0004 &0x0004 == 0x000A (10)
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0001 (1) 0x0004
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0001 (1) 0x0004 0x0004 + (1 * 4) == 0x0008 &0x0008 == 0x0014 (20)
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0002 (2) 0x0004
#include <stdio.h> int main() { int i = 0; int
things[] = {10, 20}; for (; i < 3; i++) { printf("%d\n", things[i]); } return 0; } Physical Memory Chip 0x0000 4 bytes 0x0008 0x000C 0xFFFF 0x000A (10) 0x0014 (20) 0x0002 (2) 0x0004 0x0004 + (2 * 4) == 0x000C &0x000C == ???? ????
JavaScript is especially hard.
sentry $ find node_modules -type f | wc -l 36882
sentry $ du -hs node_modules 308M node_modules
function multiply() { var rv = 1; for (var i
= 0; i < arguments.length; i++) rv += arguments[i]; return rv; } > multiply(2, 2) <- 4
test('multiply 2 * 2 to equal 4', () => {
expect(multiply(2, 2)).toBe(4); }); 100% test coverage btw
> multiply(2, 2) <- 4
> multiply(2, 2) <- 4 > multiply() <- 1
> multiply(2, 2) <- 4 > multiply() <- 1 >
multiply(1, 1) <- 3
> multiply(2, 2) <- 4 > multiply() <- 1 >
multiply(1, 1) <- 3 > multiply(1, {}) <- "2[object Object]"
Shipping code is the worst.
window.Notification.requestPermission().then(function() { new Notification("I see you."); });
Yas, I did it!
I think my computer is broken.
Step 1:
Step 1: Acceptance
This is hard. But that’s ok.
Step 2:
Step 2: Self-awareness
You won’t know everything. You will make mistakes. But that’s
OK.
Step 3:
Step 3: Do your best
Learn from mistakes. assume the worst.
How to deal with production.
Bug-free code is very rare.
Respond quickly when things are broken.
Monitoring is good.
Meet Sentry.
Error reporting
window.Notification.requestPermission().then(function() { new Notification("I see you."); });
None
None
Context is good.
Questions? I may or may not have answers. @mattrobenolt github.com/mattrobenolt
sentry.io github.com/getsentry/sentry