Math

Transcript

1. 2 3  3 4 = 2 x 43 x 3 3 x 4 = 17 12 f x=a n xna n−1 xn−1···a 1 xa 0 f x=∑ r=0 n a r xr e=lim n ∞ 1 1 n  n = 1 N ∑ i=1 N x i − x2 =2⋅∫ −1 1 1−x2 dx y=ax2bxc x 1 x 2 =0 2 4 = 1 2 y= x1 2 sen45º= 2 2 2 r [a 1 1 a 1 2 a 1 3 a 2 1 a 2 2 a 2 3 a 3 1 a 3 2 a 3 3 ] CO 2 H 2O ⇄H 2 CO 3 R 1 − R 2 ∣ C ∣ R 3 −OH