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kanaya
June 02, 2026
Education
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2026 Introduction to University Math 08
kanaya
June 02, 2026
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Transcript
pineapple.cc ࡚େֶใσʔλՊֶ෦ େֶֶೖ Introduction to University Mathematics
pineapple.cc How to take notes w ܗࣜΛܾΊΔ w ݟग़͠Λ͚ͭΔ w
ϖʔδʹςʔϚ w Օॻ͖ʹ͢Δ w ༨നΛ͢ ϊʔτͷऔΓํ Life Hacker
pineapple.cc ߨٛͷਐΊํʢୈճʙୈճʣ Agenda (Day 2 to Day 8) w େֶֶͷೖIntroduction
to University Mathematics ⭐⭐ w ֶΛ͖ʹͳΔStories about math that makes you fun ⭐ w ܭࢉػՊֶʢใՊֶʣͷڮ͠A bridge to computer science ⭐⭐⭐
pineapple.cc ධՁ Credits w ग़੮Attendance w ΫΠζͱϛχϨϙʔτQuiz and mini report
w ϨϙʔτʢҙʣReport (optional) w ʢ2ʣʢ2ʣ50 points (Q1) + 50 points (Q2)
pineapple.cc ࣭ʢ݄ʣ Question 07 (26th May 2025) w ҐஔΛ࣌ؒͰඍ͢ΔͱԿ͕ಘΒΕΔʁWhat do
you get when you di ff erentiate position with respect to time? w 1⃣ڑDistance. w 2⃣໘ੵArea. w 3⃣Velocity. w 4⃣ͦͷଞɾΘ͔Βͳ͍Other/Don’t know.
pineapple.cc ࣭ʢ݄ʣ Question 07 (26th May 2025) w ҐஔΛ࣌ؒͰඍ͢ΔͱԿ͕ಘΒΕΔʁWhat do
you get when you di ff erentiate position with respect to time? w 1⃣ڑDistance. w 2⃣໘ੵArea. w 3⃣Velocity. w 4⃣ͦͷଞɾΘ͔Βͳ͍Other/Don’t know.
pineapple.cc 🚗 t x v = dx dt
pineapple.cc 🎾 ⚽ m1 v m2 p ≜ mv
pineapple.cc p ≜ mv F = d dt p
pineapple.cc ඍdifferentiation
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pineapple.cc f′  (a) ≜ lim h→0 f(a + h)
− f(a) h
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pineapple.cc f′  (x) ≜ lim h→0 f(x + h)
− f(x) h
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pineapple.cc χϡʔτϯ๏Newton’s method
pineapple.cc ٻࠜ Root Finding f(x) = 0 զʑ͕ѻ͏ʹ͋Γ͕ͪͳ͜ͱ • ؔͷத͕Θ͔Βͳ͍
• ͕ؔෳࡶ͗ͯ͢ղ͚ͳ͍
pineapple.cc ೋ๏ Bisection method ූ߸͕ҟͳΔ
pineapple.cc χϡʔτϯɾϥϑιϯ๏ʢχϡʔτϯ๏ʣ Newton-Raphson method (Newton’s method)
pineapple.cc ෳૉcomplex
pineapple.cc x − 1 = 0
pineapple.cc x = 1
pineapple.cc x + 1 = 0
pineapple.cc x = − 1
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pineapple.cc x2 − 1 = 0
pineapple.cc x = ± 1
pineapple.cc x2 + 1 = 0
pineapple.cc x = ± −1
pineapple.cc i2 ≡ − 1
pineapple.cc (x1 + iy1) + (x2 + iyr) = (x1
+ x2) + i (y1 + y2) (x1 + iy1) (x2 + iy2) = (x1 x2 − y1 y2) + i (x1 y2 + x2 y1)
pineapple.cc z1 + z2 = z3 , (z1 , z2
, z3 ∈ ℤ) z1 z2 = z3 , (z1 , z2 , z3 ∈ ℤ) (z1 + z2) + z3 = z1 + (z2 + z3) (z1 z2) z3 = z1 (z2 z3) 0 + z = z + 0 = z 1z = z1 = z
pineapple.cc z*z = x2 + y2 where z = x
+ iy, z* = x − iy
pineapple.cc −z + z = 0 ( z* z*z) z
= 1
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pineapple.cc z = x + iy Z = [ 1
0 0 1] x + [ 0 −1 1 0 ] y = [ x −y y x ]
pineapple.cc z* = x − iy where z = x
+ iy Z* = [ x y −y x] where Z = [ x −y y x ]
pineapple.cc
pineapple.cc exp(iθ) = cos(θ) + i sin(θ) eiθ = cos(θ)
+ i sin(θ)
pineapple.cc 0 x y 1 θ p p = [
cos(θ) sin(θ)]
pineapple.cc 0 x y 1 θ p q α q
= [ cos(α) −sin(α) sin(α) cos(α) ] p p = [ cos(θ) sin(θ)] q = R(α)p
pineapple.cc 0 x y 1 p = cos(θ) + i
sin(θ) θ ℜ ℑ p
pineapple.cc 0 x y 1 θ p q α q
= (cos(α) + i sin(α)) p p = cos(θ) + i sin(θ) ℜ ℑ
pineapple.cc 0 x y 1 θ p q α q
= exp(iα)p = exp(iα)exp(iθ) = exp (i(α + θ)) p = exp(θ) ℜ ℑ
pineapple.cc exp(iα) = cos(α) + i sin(α)
pineapple.cc exp ([ 0 −α α 0 ]) = [
cos(α) 0 0 cos(α)] + [ 0 −sin(α) sin(α) 0 ] = [ cos(α) −sin(α) sin(α) cos(α) ] iα cos(α) i sin(α) R(α)
pineapple.cc exp ([ 0 −α α 0 ]) ≃ [
1 0 0 1] + [ 0 −α α 0 ] = [ 1 −α α 1 ] where α ≃ 0
pineapple.cc ෳૉhyper complex
pineapple.cc z = x + iy, where i2 = −
1 q = s + iu + jv + kw where i2 = j2 = k2 = − 1, ijk = − 1, ij = k, jk = i, ki = j, ji = − k, kj = − i, ik = − j
pineapple.cc q = ( s + ti u + vi
−u + vi s − ti ) = s ( 1 0 0 1) + t ( i 0 0 −i) + u ( 0 1 −1 0) + v ( 0 i i 0)
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William Rowan Hamilton
pineapple.cc ࣭ʢ݄ʣ Question 06 (4th June 2024) w ڏ୯ҐͳͥJͱॻ͘ͷʁWhy is
the imaginary unit written as i? w 1⃣*NBHJOBSZVOJUͷ಄จࣈ͔ͩΒBecause it is an imaginary unit. w 2⃣*NQPSUBOUOVNCFSͷ಄จࣈ͔ͩΒBecause it is an important number. w 3⃣*NQPTTJCMFWFDUPSͷ಄จࣈ͔ͩΒBecause it is an impossible vector. w 4⃣ͦͷଞɾΘ͔Βͳ͍Other/Don’t know.
pineapple.cc ҙϨϙʔτOptional report
pineapple.cc ҙϨϙʔτ Optional report w FYQ Y ΛYͰඍ͠ͳ͍͞ w ΦΠϥʔͷެ͔ࣜΒࡾ֯ؔʢTJO
DPTʣͷഒ֯ͷެࣜΛಋग़͠ͳ͍͞ w ҙͷෳૉΛY࣮ߦྻͰදݱ͠ɼ͠ࢉɼֻ͚ࢉͷنଇ͕Ұக͢Δ͜ͱ Λࣔ͠ͳ͍͞ PDFͱͯ͠LACSఏग़͢Δ͜ͱʢఏग़ҙʣ
pineapple.cc 🔎45&"./&84