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math_25
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Utree
May 08, 2019
Education
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30
math_25
Utree
May 08, 2019
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x = 1 n I ∑ i=1 xi
an = (1 − 0.6)an−1 an = a1 ( 5
2 )n−1 at = 0 ∑t i=1 a1 − ai t ΑΓ ͱͳΔUͱ͓͘ ߲ͷ͕ ٻΊΔ ຊॻͰѻΘͳ͍ͷͰɺ ,1*ͷܭࢉ͋Δ͍ϏδωεֶΛࢀর
x1 + x2 + x3 … + xn = n
∑ k=1 xi
x = x1 + x2 + x3 + … +
xn n = 1 n n ∑ k=1 xi (x1 − x)2 + (x2 − x)2 + … + (xn − x)2 n = 1 n n ∑ k=1 (xi − x)2 (x1 − x)2 + (x2 − x)2 + … + (xn − x)2 n = 1 n n ∑ k=1 (xi − x)2
None
n ∑ i=1 (ai + bi ) = n ∑
i=1 ai + n ∑ i=1 bi n ∑ i=1 cai = c n ∑ i=1 ai n ∑ i=1 c = nc . . .
1 ฏۉ = 90 + 1 10 (9 + 1
+ 9 + 1 + 6 + 4 + 8 + 3 + 9 + 0) ɹɹɹ = 95 ௐࠪڠྗऀ ຬ ਓ ਓ ਓ ਓ ̑ਓ ̒ਓ ̓ਓ ̔ਓ ̕ਓ ̍̌ਓ
1
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